Let f ( x ) = x 2 − 5 x + 6 x 2 − 6 x + 5 .

f ( x ) = ( x − 2 ) ( x − 3 ) ( x − 1 ) ( x − 5 ) The graph of f ( x ) is shown (A) If − 1 5 ⇒ 0 < f ( x ) < 1

Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeMonotonicity-Increasing-DecreasingHard2 minPYQ_2007

MathematicsHardsingle choice

Let $f (x) = \frac{x ^{2} - 6 x + 5}{x ^{2} - 5 x + 6}$ .

Options:

Answer:

Solution:

$f (x) = \frac{( x - 1 ) ( x - 5 )}{( x - 2 ) ( x - 3 )}$ The graph of $f (x)$ is shown
(A) If $- 1 < x < 1 \Rightarrow 0 < f (x) < 1$ (B) If $1 < x < 2 \Rightarrow f (x) < 0$ (C) If $3 < x < 5 \Rightarrow f (x) < 0$ (D) If $x > 5 \Rightarrow 0 < f (x) < 1$

Stream:JEE_ADVSubject:MathematicsTopic:Application of DerivativeSubtopic:Monotonicity-Increasing-Decreasing

⏱ 2mℹ️ Source: PYQ_2007

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