Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeTangents & NormalsMedium2 minPYQ_2020

MathematicsMediumsingle choice

The equation of the tangent to the curve $y = b e^{- x / a}$ at the point where it crosses the $y$ -axis is

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Answer:

Solution:

$y = b e^{- x / a}$ meets the $y$ -axis at $(0, b)$ . Again, $\frac{d y}{d x} = b e^{- x / a} (- \frac{1}{a})$ $At (0, b), \frac{d y}{d x} = b e^{0} (- \frac{1}{a}) = - \frac{b}{a}$ Therefore, required tangent is $y - b = - \frac{b}{a} (x - 0) or \frac{x}{a} + \frac{y}{b} = 1$

Stream:BITSATSubject:MathematicsTopic:Application of DerivativeSubtopic:Tangents & Normals

⏱ 2mℹ️ Source: PYQ_2020

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