The line drawn ( 4 , − 1 , 2 ) and ( − 3 , 2 , 3 ) meets the plane at right angles at the point ( − 10 , 5 , 4 ) then the equation of plane is

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TestHub · Accepted Answer

d.r's of normal to the plane are < 4 − ( − 3 ) , − 1 − 2 , 2 − 3 > 0 < 7 , − 3 , − 1 > and it passes through ( − 10 , 5 , 4 ) . Hence the required equation is 7 ( x − ( − 10 )) − 3 ( y − 5 ) − 1 ( z − 4 ) = 0 ⇒ 7 x − 3 y − z + 89 = 0

Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

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