Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Equation of the plane will be $\left|\begin{array}{ccc}x-1& y-2& z+3\\ 2-1& -2-2& 1-(-3)\\ 1& 0& 0\end{array}\right|=0$ $\Rightarrow \left|\begin{array}{ccc}x-1& y-2& z+3\\ 1& -4& 4\\ 1& 0& 0\end{array}\right|=0$ $\Rightarrow 1[4(y-2)+4(z+3)]=0$ [Expanding along $R_j]$ $\Rightarrow 4y-8+4z+12=0$ $\Rightarrow 4y+4z+4=0$ $\Rightarrow y+z+1=0$