Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Required equation is $(x+y+z-1)+\lambda (2x+3y-z+4)=0$ $$\Rightarrow (1+2\lambda )x+(1+3\lambda )y+(1-\lambda )z+(4\lambda -1)=0$$ But plane is parallel to the $\mathrm{x}$-axis $$\begin{array}{rl}& \Rightarrow \lambda =-\frac{1}{2}\\ & \Rightarrow -\frac{1}{2}y+\frac{3}{2}z-3=0\\ & \Rightarrow y-3z+6=0\end{array}$$