A car starts with constant acceleration a = 2 m / s 2 at t = 0 . Two coins are released from the car at t = 3 \& t = 4 seconds. Each coin takes 1 second to fall on ground. Then the distance between th

Question

A car starts with constant acceleration a = 2 m / s 2 at t = 0 . Two coins are released from the car at t = 3 \& t = 4 seconds. Each coin takes 1 second to fall on ground. Then the distance between the two coins (in metre) will be : (Assume coin sticks to the ground)

TestHub · Accepted Answer

Coin 1 (released at t = 3 s, v = 6 m/s) lands 6 m ahead of its release point; coin 2 (t = 4 s, v = 8 m/s) lands 8 m ahead of its own.

Between t = 3 and 4 the car covers $6 + \frac{1}{2} \times 2 \times 1 = 7 m$ . Separation $= (7 + 8) - 6 = 9 m$ .

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