Physics - Kinematics Question with Solution | TestHub

The acceleration of a particle moving only on a horizontal $\mathrm{x}-\mathrm{y}$ plane is given by $\mathrm{a}=2\mathrm{t}\hat{\mathrm{i}}+3\mathrm{t}\hat{\mathrm{j}}$, where a is in meters per second squared and t is in seconds. At t = 0 the particle has the velocity vectors $\overrightarrow{\mathrm{V}}=(5.00\mathrm{m}/\mathrm{s})\hat{\mathrm{i}}+(2.00\mathrm{m}/\mathrm{s})\hat{\mathrm{j}}$ and position vector $\overrightarrow{\mathrm{r}}=(10.00\mathrm{m})\hat{\mathrm{i}}+(10.00\mathrm{m})\hat{\mathrm{j}}$. At $t=6\mathrm{s}$, the position vector of the particle is :