The motion of a body travelling along a straight line is given by the equation dt dv = 6.0 − 3 v where v is speed in m/s and t in second. If body was at rest at t = 0 :

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PhysicsKinematics1-DMedium2 minQB

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The motion of a body travelling along a straight line is given by the equation $\frac{dv}{dt} = 6.0 - 3 v$ where v is speed in m/s and t in second. If body was at rest at $t = 0$ :

Options:(select one or more)

Answer:

A, B, D

Solution:

dv/dt = 6 - 3v gives initial acceleration 6 m/s^2 and terminal speed (a = 0) v = 2 m/s.

Solving gives v = 2(1 - e^{-3t}) m/s.

Acceleration half the initial value means 6 - 3v = 3, so v = 1 m/s, not 0.1 m/s; (C) is wrong.

Answer: A,B,D

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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