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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

A particle is moving at a speed of 10 m/s along south. After 5 s its velocity changes and becomes 10 m/s along east. What is the average acceleration during this interval:

Options:

Answer:

Solution:

$a = (10 i + 10 j) /5$ ; its magnitude is $102 /5 = 22$ $m / s^{2}$ directed north-east. Option A.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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