A car accelerates from rest at a constant rate of 2 m s - 2 for some time. Then, it retards at a constant rate of 4 m s - 2 and comes to rest. If the total time for which it remains in motion is 3 s ,

Question

A car accelerates from rest at a constant rate of 2 m s - 2 for some time. Then, it retards at a constant rate of 4 m s - 2 and comes to rest. If the total time for which it remains in motion is 3 s , Then the total distance travelled is

TestHub · Accepted Answer

Using v = u + at or v - u = at , we find that if a → is doubled, t will be halved. If t is the time for accelerations, then t 2 is the time for retardation. Now, t + t 2 = 3 or 3 t 2 = 3 t = 2 s S = 1 2 × 2 × 2 × 2 + 1 2 × 4 × 1 × 1 = 4 + 2 m = 6 m

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