A point P moves in counter clockwise direction on a circular path as shown in the figure. The movement of 'P' is such that it sweeps out a length $s = t^{3} + 5$ , where s is in metres and t is in seconds. The radius of the path is 20 m. The acceleration of 'P' when $t = 2 s$ is nearly :-

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TestHub · Accepted Answer

S = t 3 + 5 ⇒ v = 3 t 2 , a t ​ = 6 t . At t = 2 s: a t ​ = 12 , a c ​ = R v 2 ​ = 20 144 ​ = 7.2 . ∣ a ∣ = 1 2 2 + 7. 2 2 ​ ≈ 14 m / s 2 - (A).

Physics - Circular Motion Question with Solution | TestHub

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