Start Free Mock LoginAlready registered? Login here

Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2023

PhysicsEasysingle choice

A constant torque of $100 N m$ turns a wheel of moment of inertia $300 kg m^{2}$ about an axis passing through its centre. Starting from rest, its angular velocity after $3 s$ isNEET 2023 (Manipur)

Options:

Answer:

Solution:

About fixed axis $\to$ Torque $= I α$ $α = \frac{100}{300} α = \frac{1}{3} rad / s^{2}$ $\Rightarrow ω_{i} = 0 ω_{f} = ω_{i} + α t at t = 3 s ω_{f} = \frac{1}{3} \times 3 = 1 rad / s$

Stream:NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2023

Doubts & Discussion

Loading discussions...