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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A stone of mass $1 kg$ is tied at one end of a string of length $1 m$ . It is whirled in a vertical circle at a constant speed of $4 m s^{- 1}$ . The tension in the string is $6 N$ when the stone is at $(g = 10 m s^{- 2})$

Options:

Answer:

Solution:

When the string makes an angle $θ$ with the vertical, then

$T - m g c o s θ = \frac{m v^{2}}{r}$

Substituting the values, we obtain

$6 - (1) (10) cos θ = \frac{4^{2} . 1}{1}$ = 16

$cos θ = - 1$

$θ = 18 0^{o}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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