The expansion of 1.0 mole of argon proceeds so that the gas pressure increases in direct proportion to its volume. If the volume of the gas doubles in this process, the entropy change of the gas is (l

Question

The expansion of 1.0 mole of argon proceeds so that the gas pressure increases in direct proportion to its volume. If the volume of the gas doubles in this process, the entropy change of the gas is (ln 2 = 0.7)

TestHub · Accepted Answer

P ∝ V means T = PV/nR ∝ V², so doubling V makes T₂/T₁ = 4. For argon Cᵥ,ₘ = 3R/2. ΔS = Cᵥ,ₘ ln 4 + R ln 2 = (3R/2)(2 ln 2) + R ln 2 = 4R ln 2 = 4 × 2 × 0.7 = +5.6 cal/K. Matches (b).

Chemistry - Thermodynamics - II Question with Solution | TestHub

Options:

Doubts & Discussion