Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIGibb's Free EnergyMedium2 minQB

ChemistryMediumsingle choice

A reaction for which $Δ H = - 11.7 kJ mol^{- 1}$ and $Δ S = - 105 JK^{- 1} mol^{- 1}$ would be spontaneous when temperature is

Answer:

Solution:

$Δ G$ = (–)ve for spontaneous reaction.

$Δ G = Δ H - T Δ S$ .

$= - 11.69 \times 10^{3} + 105 \times T < 0$

If $T < 111.4 K$ , then $Δ G$ is (–)ve and the reaction is spontaneous.

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy

⏱ 2mℹ️ Source: QB

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