Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSMedium2 minQB
ChemistryMediummatching list
Match Column I with Column II
Column I | Column II |
|---|---|
P) Reversible isothermal expansion of an ideal gas | i) Δ Ssys = Δ Ssurr = Δ Stotal = 0 |
Q) Reversible adiabatic expansion of an ideal gas | ii) Δ H = Δ U = Δ Stotal = 0 |
R) Adiabatic free expansion | iii) Δ Stotal > 0 |
| iv) q = 0 |
Options:
Answer:
D
Solution:
(P) For an ideal gas at constant temperature Δ U = Δ H = 0, and a reversible process has Δ Stotal = 0 — ii (heat flows, so not iv). (Q) A reversible adiabatic process has q = 0 and is isentropic: Δ Ssys = Δ Ssurr = Δ Stotal = 0 — i,iv. (R) Expansion into a vacuum does no work and is adiabatic, q = 0; being irreversible it creates entropy, Δ Stotal > 0 — iii,iv.
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
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