1 mol of an ideal monoatomic gas follows a reversible cyclic process ABCA, as shown in the diagram.
AB → Reversible isothermal at 300 K
CA → Reversible adiabatic
Determine the efficiency of the thermodynamic cycle ABCA.
[Use $R = 0.08 L - a t m / K - m o l$ ; $ln 2 = 0.7$ ]

Question

1 mol of an ideal monoatomic gas follows a reversible cyclic process ABCA, as shown in the diagram.

AB → Reversible isothermal at 300 K

CA → Reversible adiabatic

Determine the efficiency of the thermodynamic cycle ABCA.

[Use $R = 0.08 L - a t m / K - m o l$ ; $ln 2 = 0.7$ ]

TestHub · Accepted Answer

w A B ​ w BC ​ w C A ​ P C ​ w C A ​ η ​ = − 24 ln ( v A ​ v B ​ ​ ) = − 72 ln ( 2 ) = − 50.4 l i t a t m = zero = ( γ − 1 ) − ( P C ​ V C ​ − P A ​ V A ​ ) ​ = P A ​ ( v C ​ v A ​ ​ ) γ = 24 × ( 8 1 ​ ) 5/3 = 4 3 ​ a t m = 2/3 ( 24 − 6 ) ​ = + 27 l i t a t m = t o t a l h e a t g ain ∣ N e tw or k d o n e ∣ ​ = 50.4 23.4 ​ = 252 117 ​ = 0.4642 ​

Chemistry - Thermodynamics - II Question with Solution | TestHub

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