Two glass bulbs of internal volumes 0.5 and 0.3 litre respectively are connected by a narrow tube of negligible volume. The pressure of air in the vessel in 75 cm Hg at 2 7 ∘ C . The smaller bulb is i

Question

Two glass bulbs of internal volumes 0.5 and 0.3 litre respectively are connected by a narrow tube of negligible volume. The pressure of air in the vessel in 75 cm Hg at 2 7 ∘ C . The smaller bulb is immersed in a bath at 2 ∘ C and the larger bulb in a bath at 10 2 ∘ C . Calculate final pressure in cm of Hg in the bulbs neglecting the expansion of glass. [ 0 ∘ C ≡ 273 K ]

TestHub · Accepted Answer

Initial: Total volume = 0.5 + 0.3 = 0.8 L P 1 ​ = 75 c m H g , T 1 ​ = 27° C = 300 K After heating: Small bulb ( 0.3 L ) → 2° C = 275 K Large bulb ( 0.5 L ) → 102° C = 375 K Using ideal gas relation (moles conserved): T 1 ​ P 1 ​ V ​ = P ( 275 0.3 ​ + 375 0.5 ​ ) 300 75 × 0.8 ​ = P ( 275 0.3 ​ + 375 0.5 ​ ) Solving carefully gives: P ≈ 82.5 c m H g

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