Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSEasy2 minQB
ChemistryEasysingle choice
In a process, a system absorbs 1.20 kJ of heat at 300 K and its entropy increases by 4.0 J/K. The correct information regarding the process is
Options:
Answer:
C
Solution:
q/T = 1200/300 = 4.0 J/K, equal to Δ S. Δ S = q/T holds for a reversible path (irreversible would give Δ S > q/T, and Δ S < q/T is impossible). Nothing is said about constant pressure. Matches (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
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