TestHub
TestHub

Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIFree Energy and EquilibriumEasy2 minPYQ_2023
ChemistryEasymatching list

For independent process at 300 K.

ProcessΔH/kJmol-1ΔS/JK-1
A-25-80
B-2240
C25-50
D2220

The number of non-spontaneous process from the following is _____ .

Answer:
2
Solution:

The relation between change in Gibbs free energy, change in enthalpy and change in entropy can be written as follows,

ΔG=ΔH-TΔS

If G is +ve , then the process is said to be non-spontaneous and if  G is -ve then the process is said to be spontaneous.

A:ΔGJmol-1=-25×103+80×300:-ve

B:ΔGJmol-1=-22×103-40×300:-ve

C:ΔGJmol-1=25×103+300×50;+ve

D:ΔGJmol-1=22×103-20×300:+ve

Processes C and D are non-spontaneous.

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
2mℹ️ Source: PYQ_2023

Doubts & Discussion

Loading discussions...