Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIGibb's Free EnergyMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

In a closed vessel at 27ºC, A(s) is decomposed as follows:

$2 A (s) \to 2 B (g) + C (g)$

Given: $Δ H^{\circ} = 57.9 k c a l / m o l$ and $Δ S^{\circ} = 200 c a l / (m o l$ /K).

Also, given $R = 2 c a l / (m o l$ -K) and $ln 2 = 0.7$ .

$Δ G^{o}$ for the reaction is $(cal / mol)$

Answer:

Solution:

Question Explanation:

Question is asking about $Δ G^{\circ}$ for the reaction.

Concept:

This question is based on Gibb's free energy.

Solution:

$2 A_{(s)} \to 2 B_{(g)} + C_{(g)}; Δ H^{\circ} = 57.9 KCal / mol$

$Δ S^{\circ} = 200 Cal / mol . K$

$Δ G^{\circ} = Δ H^{\circ} - T Δ S^{\circ}$

$Δ G^{\circ} = 57.9 - \frac{300 \times 200}{1000}$

$Δ G^{\circ} = - 2.1 KCal / mol$ or $- 2100 Cal / mol$

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy

⏱ 2mℹ️ Source: QB

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