Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IICarnot Cycle/Cyclic processHard2 minQB
ChemistryHardmultiple choice

For the cyclic process given below, in which A to B is reversible and B to A is irreversible, which of the following relations are correct?

figure

Options:(select one or more)

Answer:
A, B, D
Solution:

(a) Entropy change along the reversible path: true. (c) For the irreversible path, SA - SB > ∫BA δ qirr/T (Clausius inequality), so equality is false. (d) Adding the paths, ∮ δ q/T = (SB - SA) + ∫BA δ qirr/T < (SB - SA) + (SA - SB) = 0: true. (b) The surroundings receive the heat the system loses, so Δ Ssurr = -∮ δ q/T > 0; with Δ Ssys = 0 over the cycle this makes Δ Suniv > 0: true. Ans: (a), (b), (d).

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
⏱ 2mℹ️ Source: QB

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