Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICarnot Cycle/Cyclic processMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
One mole of a monoatomic ideal gas is used as a working substance in an engine working in the following reversible cycle: process AB = isobaric compression; process BC = adiabatic compression; process CD = isochoric heating; process DA = isothermal expansion. The ratio of maximum to minimum volume and temperature during the cycle is 6√2 and 3, respectively. The maximum temperature in the cycle is 900 K.
The change in internal energy of gas in the process BC is
Options:
Answer:
C
Solution:
ΔUBC = n·Cv·ΔT = 1 × (3/2 × 8.314) × (600 − 300) = 12.47 × 300 ≈ 3741 J ≈ 3.74 kJ, positive because adiabatic compression raises the temperature. Matches (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
