TestHub
TestHub

Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IICalculation of DSHard2 minPYQ_2021
ChemistryHardmatching list

For a given chemical reactionABat300 Kthe free energy change is-49.4 kJ mol-1and the enthalpy of reaction is51.4 kJ mol-1.The entropy change of the reaction is _________JK-1 mol-1.

Answer:
336
Solution:

Given chemical reaction:

AT=300 KB[ΔG]P,T=-49.4 kJ/mol

ΔHrxn=51.4 kJ/mol

ΔSrxn=?

From the relation [ΔG]P,T=ΔH-TΔS

ΔSrxn=ΔHrxn-[ΔG]P,TT

=[51.4-(-49.4)]×1000300JmolK

ΔSrxn=336JmolK

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...