A reaction at 1 bar is non-spontaneous at low temperature but becomes spontaneous at high temperature. Identify the correct statement about the reaction among the following:

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TestHub · Accepted Answer

∆ G = ∆ H – T ∆ S (For Spontaneity) ( ∆ G < 0 ) So If ∆ H > 0 and ∆ S > 0 for spontaneity then the process is feasible at high temperature and non-feasible at low temperature.

Chemistry - Thermodynamics - II Question with Solution | TestHub

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