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Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIFree Energy and EquilibriumHard2 minPYQ_2015
ChemistryHardmatching list

Match the thermodynamic processes given under Column I with the expressions given under Column II.

 Column I Column II
A.Freezing of water at 273 K and 1 atmP.q=0
B.Expansion of 1 mol of an ideal gas into a vacuum under isolated conditionsQ.w=0
C.Mixing of equal volumes of two ideal gases at constant temperature and pressure in an isolated containerR.ΔSsys<0
D.Reversible heating of H2(g) at 1 atm from 300 K to 600 K, followed by reversible cooling to 300 K at 1 atmS.ΔU=0
  T.ΔG=0

Options:

Answer:
C
Solution:

A -H2O(l)H2O(s)at 273 K. & 1 atm
H=-ve=q
Ssys<0, G=0
w0(as water expands on freezing),U0
B - Free expansion of ideal gas.
q = 0
w = 0
U=0
Ssys>0
G<0
C - Mixing of equal volume of ideal gases at constant pressure & temp in an isolated container
q = 0, w = 0,U=0,Ssys>0,G<0
D -H2g300 KReversibleHeating, 1 atm600 K    ReversibleCooling, 1 atm300 K
q = 0, w = 0, U=0,G=0,Ssys=0

Stream:JEE_ADVSubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
2mℹ️ Source: PYQ_2015

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