Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IIFree Energy and EquilibriumHard2 minPYQ_2015
ChemistryHardmatching list
Match the thermodynamic processes given under Column I with the expressions given under Column II.
| Column I | Column II | ||
| A. | Freezing of water at 273 K and 1 atm | P. | |
| B. | Expansion of 1 mol of an ideal gas into a vacuum under isolated conditions | Q. | |
| C. | Mixing of equal volumes of two ideal gases at constant temperature and pressure in an isolated container | R. | |
| D. | Reversible heating of at 1 atm from 300 K to 600 K, followed by reversible cooling to 300 K at 1 atm | S. | |
| T. |
Options:
Answer:
C
Solution:
A -at 273 K. & 1 atm
(as water expands on freezing),
B - Free expansion of ideal gas.
q = 0
w = 0
C - Mixing of equal volume of ideal gases at constant pressure & temp in an isolated container
q = 0, w = 0,,,
D -
,,
Stream:JEE_ADVSubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
⏱ 2mℹ️ Source: PYQ_2015
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