Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IICalculation of DSMedium2 minPYQ_2011

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The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of $10 dm^{3}$ to a volume of $100 dm^{3}$ at $2 7^{\circ} C$ is :

Options:

Answer:

Solution:

For an ideal gas, for isothermal reversible process, $Δ S = 2.303 nR lo g (\frac{v _{2}}{v _{1}}) = 2.303 \times 2 \times 8.314 \times lo g (\frac{100}{10}) = 38.3 J mol^{- 1} \cdot k^{- 1}$

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS

⏱ 2mℹ️ Source: PYQ_2011

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