An amount of 2 mole of CO was in the small cubical container of length, (l = a) at 57 ° C. The gas was taken out completely from the small container and put into large container (l = 2a) at the same t

Question

An amount of 2 mole of CO was in the small cubical container of length, (l = a) at 57^°C. The gas was taken out completely from the small container and put into large container (l = 2a) at the same temperature. What is the change in entropy, if it is assumed that the process is reversible and gas is behaving as an ideal gas?

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Answer:

A

Solution:

Volume ratio = (2a)³/a³ = 8. Isothermal ideal gas: Δ S = nRln(V₂/V₁) = 2 × 8.314 × ln 8 = 2 × 8.314 × 2.079 = 34.58 J/K (positive, expansion). Matches (a).

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Volume ratio = (2a) 3 /a 3 = 8. Isothermal ideal gas: Δ S = nRln(V 2 /V 1 ) = 2 × 8.314 × ln 8 = 2 × 8.314 × 2.079 = 34.58 J/K (positive, expansion). Matches (a).

Chemistry - Thermodynamics - II Question with Solution | TestHub

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