Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IDH/DU for reactionHard2 minQB
ChemistryHardnumerical
Only at extremely high pressure does Δ H - Δ U for condensed state reactions become significantly different than zero. Determine the pressure (in bar) at which Δ H - Δ U is equal to -1.0 kJ for the reaction, C(graphite) → C(diamond). For graphite and diamond, densities are 2.25 and 3.51 g/ml, respectively.
Answer:
5223.00
Solution:
Δ H - Δ U = Δ(PV) = PΔ V (P >> 1 bar). Δ V = 12(1/3.51-1/2.25) = 12(0.28490-0.44444) = -1.9145 cm3 = -1.9145×10-6 m3/mol. P = (-1000)/(-1.9145×10-6) = 5.223×108 Pa = 5223 bar. Ans = 5223.
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:DH/DU for reaction
⏱ 2mℹ️ Source: QB
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