Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minQB
ChemistryEasysingle choice
Passage / Comprehension
As a result of the isobaric heating by Δ T = 60 K, one mole of a certain ideal gas obtains an amount of heat Q = 1.25 kJ. (R = 8.314 J/mol K)
The increment of its internal energy (in kJ) is
Options:
Answer:
D
Solution:
Δ U = Q - w = 1.25 - 0.50 = 0.75 kJ. Matches (d).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
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