Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IAdiabatic Process/PolytropicHard2 minQB
ChemistryHardsingle choice

A diatomic ideal gas at pressure P1 and volume V1 is expanded reversibly and adiabatically until its RMS speed falls to one-third of its initial value. It is then compressed isothermally to a volume V1/2. The final pressure is

Options:

Answer:
A
Solution:

urms ∝ √(T), so T2 = T1/9 after the adiabatic step (this needs V2/V1 = 92.5 = 243 but the intermediate volume is not needed). The isothermal step keeps T3 = T1/9. From P = nRT/V: (P3)/(P1) = (T3)/(T1)·(V1)/(V3) = 1/9× 2 = 2/9. Matches (a).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
⏱ 2mℹ️ Source: QB

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