Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IIsothermal Process/Isobaric/IsochoricEasy2 minQB
ChemistryEasysingle choice
An ideal gaseous sample at initial state (P0, V0, T0) is allowed to expand to volume 2V0 using two different processes. For the first process, the equation of process is 2PV2 = K1 and for the second process, the equation of the process is PV = K2. Then
Options:
Answer:
B
Solution:
Both start from the same state, so K1 = 2P0V02 and K2 = P0V0. Process 1 (PV2 = const): W1 = ∫V02V0(P0V02)/(V2)dV = P0V02(1/(V0) - 1/(2V0)) = 0.5 P0V0. Process 2 (isothermal): W2 = P0V0ln 2 = 0.693 P0V0. So W2 > W1, which is (b).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Isothermal Process/Isobaric/Isochoric
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