Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IDH/DU for reactionMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

The molar enthalpy of vaporization of benzene at its boiling point (350 K) is $30.84 kJmol^{- 1}$ . [Given : $R = 8.314 J / K - mol$ ]

What is the molar internal energy change (in kJ) ?

Answer:

27.93

Solution:

To find the molar internal energy change ( $Δ U$ ),

use the first law of thermodynamics: $Δ U = q + w$ .

Given $q = + 30.0$ kJ (heat absorbed) and $w = - 2.07$ kJ (work done by the system).

$Δ U = 30.0 k J + (- 2.07 k J) = 27.93 k J$ .

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:DH/DU for reaction

⏱ 2mℹ️ Source: QB

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