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Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2020

ChemistryEasysingle choice

In an isothermal process at 300 K, 1 mole of an ideal gas expands from a pressure 100 atm against an external pressure of 50 atm. Then total entropy change (Cal $K^{- 1}$ ) in the process is –

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Answer:

Solution:

$Δ S_{s y s} = 1 \times 2 \times 2.303 l o g \frac{100}{50} ≃ 1.39 C a l K^{- 1}$
$Δ S_{s u r r} = \frac{- 1 \times 2 \times 300 (1 - \frac{50}{100})}{300} = - 1.0 C a l K^{- 1}$
$Δ S_{t o t a l} = + 0.39 c a l K^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2020

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