1 mole ideal monoatomic gas follows process V 2 T = constant, then molar heat capacity of gas is (in terms of R)

C m C m C m T − 2 T − 2 ( n − 1 ) n = C v + 1 − x R = 2 3 R + 1 − ( − 1 ) R = 2 R = k = T ( n − 1 ) = − 2 = − 1

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ChemistryThermodynamics - IAdiabatic Process/PolytropicMedium2 minQB

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Passage / Comprehension

Polytropic process obeys the relation $PV^{x}$ = constant where x is a polytropic index. Value of x decides the type of process that can be obtained.

1 mole ideal monoatomic gas follows process $\frac{T}{V ^{2}} =$ constant, then molar heat capacity of gas is (in terms of R)

Answer:

2.00

Solution:

$C_{m} C_{m} C_{m} T^{- 2} T^{- 2} (n - 1) n = C_{v} + \frac{R}{1 - x} = \frac{3 R}{2} + \frac{R}{1 - ( - 1 )} = 2 R = k = T^{(n - 1)} = - 2 = - 1$

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic

⏱ 2mℹ️ Source: QB

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