Chemistry - Thermodynamics - I Question with Solution | TestHub
Match Column I (Relation) with Column II (Holds for)
Column I | Column II |
|---|---|
P) Δ H = Δ U + Δ ng RT | i) Isochoric process, only PV work, any substance |
Q) qV = Δ U | ii) Ideal gas undergoing any change of state |
R) Δ H = nCP,mΔ T | iii) Adiabatic process, only PV work, any substance |
S) w = Δ U | iv) Reaction with gaseous and condensed species at constant T |
Options:
Answer:
Solution:
Δ H = Δ U + Δ ngRT comes from the enthalpy definition applied to a reaction at constant temperature, neglecting condensed-phase volumes (P – iv). At constant volume no PV work is done, so qV = Δ U for any substance (Q – i). For an ideal gas H is a function of T alone, so Δ H = nCP,mΔ T for any change of state (R – ii). With q = 0 the first law gives w = Δ U (S – iii).
