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ChemistryThermodynamics - IDH/DU for reactionMedium2 minQB
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Match Column I (Relation) with Column II (Holds for)

Column I

Column II

P) Δ H = Δ U + Δ ng RT

i) Isochoric process, only PV work, any substance

Q) qV = Δ U

ii) Ideal gas undergoing any change of state

R) Δ H = nCP,mΔ T

iii) Adiabatic process, only PV work, any substance

S) w = Δ U

iv) Reaction with gaseous and condensed species at constant T

Options:

Answer:
C
Solution:

Δ H = Δ U + Δ ngRT comes from the enthalpy definition applied to a reaction at constant temperature, neglecting condensed-phase volumes (P – iv). At constant volume no PV work is done, so qV = Δ U for any substance (Q – i). For an ideal gas H is a function of T alone, so Δ H = nCP,mΔ T for any change of state (R – ii). With q = 0 the first law gives w = Δ U (S – iii).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:DH/DU for reaction
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