Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IIsothermal Process/Isobaric/IsochoricMedium2 minQB
ChemistryMediumnumerical
The final volume (in L) of one mole of an ideal gas initially at 27°C and 12.315 atm pressure, if it absorbs 420 cal of heat during a reversible isothermal expansion, is
Answer:
4.00
Solution:
V₁ = nRT/P = (0.0821 × 300)/12.315 = 2 L. q = W = nRT ln(V₂/V₁) ⇒ 420 = 1 × 2 × 300 × ln(V₂/2) ⇒ ln(V₂/2) = 0.7 ⇒ V₂/2 = e⁰·⁷ ≈ 2, so V₂ = 4 L.
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Isothermal Process/Isobaric/Isochoric
⏱ 2mℹ️ Source: QB
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