The pressure and density of a diatomic gas (γ = 7/5) change from (P 1 , d 1 ) to (P 2 , d 2 ) adiabatically. If d 2 /d 1 = 32, then what is the value of P 2 /P 1 ?

Adiabatic: P/d γ = const, so P 2 /P 1 = (d 2 /d 1 ) γ = 32 7/5 = 2 5 × 7/5 = 2 7 = 128. Matches (c).

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ChemistryThermodynamics - IAdiabatic Process/PolytropicEasy2 minQB

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The pressure and density of a diatomic gas (γ = 7/5) change from (P₁, d₁) to (P₂, d₂) adiabatically. If d₂/d₁ = 32, then what is the value of P₂/P₁?

Answer:

Solution:

Adiabatic: P/d^γ = const, so P₂/P₁ = (d₂/d₁)^γ = 32^7/5 = 2^{5 × 7/5} = 2⁷ = 128. Matches (c).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic

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