A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of $37 . 0^{\circ} C$ . As it does so, it absorbs 208 J of heat. The values of q and w for the process will be
(R = 8.314 J/mol K) (ln7.5 = 2.01)

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TestHub · Accepted Answer

Since, temperature remains constant, the process will be isothermal by nature.
For Isothermal reversible expansion:
$Δ E = 0 = q + w$
$q = - w$
$q = + 208 J$ {heat absorbed so +ve}
$w = - 208 J$ {expansion so work done is -ve}

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