Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IIsothermal Process/Isobaric/IsochoricMedium2 minQB
ChemistryMediummultiple choice

Select the correct option(s):

Options:(select one or more)

Answer:
A, B, C
Solution:

(a) Energy per mole is intensive: true. (b) For V ≫ nb the van der Waals reversible work is wby = nRTln(V2/V1) - an2(1/V1 - 1/V2), which is smaller than the ideal value nRTln(V2/V1): true. (c) This is the definition of a reversible process: true. (d) Isothermal expansion of an ideal gas has Δ U = 0, so q = wby. The reversible path does the maximum work, so it absorbs the most heat: false. Ans: (a), (b), (c).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Isothermal Process/Isobaric/Isochoric
⏱ 2mℹ️ Source: QB

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