Start Free Mock LoginAlready registered? Login here

Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2020

ChemistryEasysingle choice

Find the entropy change for vaporisation of water to steam at $100 ° C$ in $J K^{- 1} m o l^{- 1}$ if heat of vaporisation is 40.8 kJ $m o l^{- 1}$ .

Options:

Answer:

Solution:

$Δ S = \frac{Δ H_{v}}{T}$
$Δ H = 40.8$ kJ/mol
$= 40.8 \times 1 0^{3}$ J/mol
$T = 373$ K
So $Δ S = \frac{40.8 \times 1 0^{3}}{373} = 109.38 J K^{- 1} m o l^{- 1}$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...