Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IAdiabatic Process/PolytropicHard2 minQB
ChemistryHardinteger
An ideal gas sample (γ = 5/3) is expanded adiabatically from 4 atm, 400 K against a constant external pressure of 1 atm. If the decrease in temperature is 'x' kelvin then calculate (x/10).
Answer:
12
Solution:
Irreversible adiabatic: q = 0, so ΔU = -Pext ΔV.
Cv = R/(γ - 1) = R/(2/3) = 1.5R.
- 400) = -1 × (nRT2/1 - nR × 400/4).
- 600 = - + 100, so = 700 and = 280 K.
x = 400 - 280 = 120, so x/10 = 12.
Answer: 12.
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
⏱ 2mℹ️ Source: QB
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