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ChemistryThermodynamics - IIsothermal Process/Isobaric/IsochoricEasy2 min

ChemistryEasysingle choice

An ideal gas is taken around the cycle ABCA as shown in $P - V$ diagram. The value of q for the cycle is equal to :

Answer:

Solution:

Work done by the gas in the cyclic process $=$ Area bounded $(ABCA) = - 5 P_{1} V_{1}$

Therefore, $q = - W = 5 P_{1} V_{1}$ (cyclic process, so $Δ U = 0$ ).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Isothermal Process/Isobaric/Isochoric

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