The enthalpy change ( Δ H ) for the reaction, N 2 ( g ) + 3 H 2 ( g ) → 2 NH 3 ( g ) is − 92.38 kJ at 298 K . The internal energy change Δ U at 298 K is

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The enthalpy change ( Δ H ) for the reaction, N 2 ( g ) ​ + 3 H 2 ( g ) ​ → 2 NH 3 ( g ) ​ is − 92.38 kJ at 298 K . The internal energy change Δ U at 298 K is

TestHub · Accepted Answer

Δ H = Δ U + Δ n RT [where Δ n = no. of molecules of products - no. of molecules of reactants] or, − 92.38 × 1000 = Δ U − 2 × 8.314 × 298 or, Δ U = − 87424 J = − 87.424 kJ .

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