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Chemistry - Thermodynamics - 1 Question with Solution | TestHub

ChemistryThermodynamics - 1Adiabatic Process/PolytropicMedium2 minQB

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When an ideal monoatomic gas undergoes an adiabatic expansion, its temperature and volume are related by the equation $TV^{n} =$ constant, the value of n will be

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Solution:

For an adiabatic process, $P V^{γ} = co n s t an t$ . Using $P V = n RT$ , we derive $T V^{γ - 1} = co n s t an t$ . For monoatomic gas, $γ = 5/3$ . Thus, $n = γ - 1 = 2/3 \approx 0.67$ .

Stream:JEESubject:ChemistryTopic:Thermodynamics - 1Subtopic:Adiabatic Process/Polytropic

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