Chemistry - Thermodynamics - 1 Question with Solution | TestHub

Work is done by a system irreversibly$\Rightarrow \left({\mathrm{W}}_{\mathrm{sys}}\right)=-(1\times {10}^5)\mathrm{N}/{\mathrm{m}}^2\times (2.5-2)\times {10}^{-3}{\mathrm{m}}^3=50\mathrm{}$
From 1st Law of Thermodynamics:$∆\mathrm{U}={\mathrm{w}}_{\mathrm{sys}}+{\mathrm{q}}_{\mathrm{sys}}$$∆\mathrm{U}=-50+58.63\mathrm{J}=8.63\mathrm{ J}$