Chemistry - Thermodynamics - I Question with Solution | TestHub

(A) ${\mathrm{CH}}_2=\mathrm{CH}-\mathrm{CH}={\mathrm{CH}}_2\to {\mathrm{CH}}_2=\mathrm{C}=\mathrm{CH}-{\mathrm{CH}}_{2(\mathrm{g})}$

$\because \Delta {\mathrm{n}}_{\mathrm{g}}=0$

Pressure will decrease due to decrease in temperature

& $\mathrm{W}=0$

(B) ${\mathrm{H}}_2{\mathrm{O}}_{(\because )}\to {\mathrm{H}}_2{\mathrm{O}}_{(\mathrm{g})}$

$\because \Delta \mathrm{U}=0$ & $\Delta$ P.E. $>0$

$\because \Delta$ K.E. $<0$ & $\Delta \mathrm{T}<0$

(C) ${\mathrm{CH}}_{4(\mathrm{g})}+2{\mathrm{O}}_{2(\mathrm{g})}\to {\mathrm{CO}}_{2(\mathrm{g})}+2{\mathrm{H}}_2{\mathrm{O}}_{(\mathrm{g})}$

$\Delta {\mathrm{n}}_{\mathrm{g}}=0$

Due to release of heat, temperature will increase which increases pressure inside container.

(D) During neutralisation heat release which increases temperature inside container.