A system goes from one state to another by path I with heat absorbed 5 kcal and work done 0 erg. For the same change of state by path II, heat absorbed is 5.9 kcal and work done is 0.6 w max , where w

Question

A system goes from one state to another by path I with heat absorbed 5 kcal and work done 0 erg. For the same change of state by path II, heat absorbed is 5.9 kcal and work done is 0.6 w_max, where w_max is the work done if the change were carried out reversibly. Find the magnitude of w_max in J. (1 cal = 4.2 J)

Answer:

6300.00

Solution:

Δ U = 5 - 0 = 5 kcal. Path II: 5 = 5.9 - 0.6 w_max, so 0.6 w_max = 0.9 kcal, w_max = 1.5 kcal = 1500×4.2 = 6300 J. Ans = 6300.

TestHub · Accepted Answer

Δ U = 5 - 0 = 5 kcal. Path II: 5 = 5.9 - 0.6 w max , so 0.6 w max = 0.9 kcal, w max = 1.5 kcal = 1500×4.2 = 6300 J. Ans = 6300.

Chemistry - Thermodynamics - I Question with Solution | TestHub

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