Chemistry - Thermodynamics - 1 Question with Solution | TestHub

$\therefore {10}^6 \mathrm{a}\mathrm{t}\mathrm{o}\mathrm{m}\mathrm{s} \mathrm{o}\mathrm{f} {\mathrm{I}}_{\left(\mathrm{g}\right)}=4.9\times {10}^{-13}\mathrm{J}$
$\therefore 6.023\times {10}^{23} \text{atoms} \text{of} {\text{I}}_{\left(\text{g}\right)}=\frac{4.9\times {10}^{-13}\times 6.023\times {10}^{23}\text{J}}{{10}^6}$
$\mathrm{E}=295.127 \mathrm{k}\mathrm{J}/\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}$
Also$\mathrm{E}=\frac{295.127\times {10}^3}{1.60\times {10}^{-19}\times 6.023\times {10}^{23}}\simeq 3 \mathrm{e}\mathrm{V}$