Chemistry - Thermodynamics - 1 Question with Solution | TestHub

Total work done = area of rectangle of 15 atm height and 10 L width- area of half of circle
$15\left(20-10\right)-\left(\frac{\mathrm{\pi }\times 5^2}{2}\right)$
$=\left(150-\frac{25\mathrm{\pi }}{2}\right)$